Correct option is A
Given:
Length of the diagonal = 32m32m32 \, \text{m} 32
Offsets = 6m and 10m6m6 \, \text{m}6m10m10 \, \tex
Formula used:
Area of quadrilateral =
where, d is the diagonal , a and b are offsets
Solution:
Area = 32 (6 + 10)
= 16 16
= 256