The compound interest of Rs. 6,000 in two years, if the rate of interest is 2.5% per annum for the first year and 2% per annum for the second year, will be:

Principal P = 6000

Rate of interest for the first year, $$R_1 = 2.5\%$$​​

Rate of interest for the second year, $$R_2 = 2\%$$​​

Time period = 2 years

If compounding rate of interest is different for each year, then;

​$$A​= P× \left(1+\frac{R_1}{100}​​\right) \times\left(1+\frac{R_2}{100}​​\right)$$​​

C.I = A - P

Where, A = Amount, P = Principal, C.I = Compound Interest. 

Solution: 

Putting the values in the formula;

​$$A​= 6000× \left(1+\frac{2.5}{100}​​\right) \times\left(1+\frac{2}{100}​​\right) \\ \ \\ A​= {6\cancel{000}}× \left(\frac{1025}{1\cancel{000}}​​\right) \times\left(\frac{102}{100}​​\right) \\ \ \\ = 6273$$ 

Thus,  Compound Interest = 6273 - 6000 = Rs. 273