The average of X and Y is 40, that of Y and Z is 38, and that of Z and X is 42. Find the average of X, Y and Z.
Given:
Average of X and Y = 40
Average of Y and Z = 38
Average of Z and X = 42
Formula Used:
Average of two numbers
Solution:
From the given information:
X + Y = 80
38
Y + Z = 76
Z + X = 84
Now, we add all three equations:
(X + Y) + (Y + Z) + (Z + X) = 80 + 76 + 84
2X + 2Y + 2Z = 240
X + Y + Z == 120
Average of X, Y, and Z
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Suggested Test Series
Suggested Test Series
The average age of 14 persons is 13 years. If the age of 15th persons is added, then the average remains same. What is the age (in years) of the 15th person?
The average of 17 consecutive natural numbers is 30. 5 previous consecutive natural numbers to these 17 natural numbers are also included. What is the smallest number among these 22 numbers?
Average age of a group of 16 boys is 24 years. Two boys with ages 19 years and 18 years left the group. One boy with age 43 years joined the group. What is the new average age (in years) of the group?
Average of 6 numbers is P. One number is removed. New average is P + 5. Which number was removed?
Average of 7 numbers is 28. One of these numbers is 22. 22 is replaced with a new number. New average becomes 30. What is that new number?
What is the average of the squares of first 14 natural numbers?
Average of first 'N' multiples of 3 is 66. What is the value of 'N'?
In a class, the average age of 28 boys is 13 years. Two boys whose ages are 'x' years and 21 years leave the class. If the new average age of the class is 13 years, then what is the value of 'x'?
The average of five numbers is 40. If one number is removed, then the average becomes 36. What is the removed number?
The average of the first 62 even natural numbers is:
