The average of 5 consecutive numbers A, B, C, D and E is 48. What is the product of A and E?

Correct option is B

As they are consecutive, the numbers can be represented as-
​$$a, a+1, a+2, a+3,a+4.$$​​
Average of these numbers= 48
​$$48= \frac{ (a+a+1+a+2+a+3+a+4)}{5}\\ \ \\48= \frac {(5a+10)}{5} \\ \ \\48= a+2 \\ \ \\a= 46$$​​
Therefore, $$E = 46 + 4 = 50.$$​​
Product of A and E = 46 × 50 = 2300.