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The area of the triangle formed by the line 2x - 4y – 7 = 0 with the coordinate axis is:
Question

The area of the triangle formed by the line 2x - 4y – 7 = 0 with the coordinate axis is:

A.

498 unit2\tfrac{49}{8} \space\text{unit}^2​​

B.

494 unit2\tfrac{49}{4} \space\text{unit}^2

C.

492 unit2\tfrac{49}{2} \space\text{unit}^2

D.

4916 unit2\tfrac{49}{16} \space\text{unit}^2

Correct option is D

Given:

The equation of the line is:

2x−4y−7=0

Formula Used:

A line intersects the x-axis when y=0 and the y-axis when x=0.
The area of a triangle formed by the x-axis and y-axis is given by:

Area=12×Intercept on x-axis×Intercept on y-axis\text{Area} = \frac{1}{2} \times \text{Intercept on x-axis} \times \text{Intercept on y-axis}​​

Solution:

Find x-intercept

Set y=0 in the equation:

2x - 4(0) - 7 = 0

x =72 \frac{7}{2}​​

So, x-intercept =(72,0)\left(\frac{7}{2}, 0\right)​​

Find y-intercept

Set x=0 in the equation:

2(0)−4y−7=0

y = -74\frac{7}{4}​​

So, y-intercept = (0,74)\left(0, -\frac{7}{4}\right)

Since we take absolute values for area calculations, we use 74\frac{7}{4}
74\frac{7}{4}​​​

Area=12×72×74\text{Area} = \frac{1}{2} \times \frac{7}{2} \times \frac{7}{4}​​

Area=12×498=4916 \frac{1}{2} \times \frac{49}{8}= \frac{49}{16}

Option (D) is right.

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