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    The area of the triangle formed by the line 2x - 4y – 7 = 0 with the coordinate axis is:
    Question

    The area of the triangle formed by the line 2x - 4y – 7 = 0 with the coordinate axis is:

    A.

    498 unit2\tfrac{49}{8} \space\text{unit}^2​​

    B.

    494 unit2\tfrac{49}{4} \space\text{unit}^2

    C.

    492 unit2\tfrac{49}{2} \space\text{unit}^2

    D.

    4916 unit2\tfrac{49}{16} \space\text{unit}^2

    Correct option is D

    Given:

    The equation of the line is:

    2x−4y−7=0

    Formula Used:

    A line intersects the x-axis when y=0 and the y-axis when x=0.
    The area of a triangle formed by the x-axis and y-axis is given by:

    Area=12×Intercept on x-axis×Intercept on y-axis\text{Area} = \frac{1}{2} \times \text{Intercept on x-axis} \times \text{Intercept on y-axis}​​

    Solution:

    Find x-intercept

    Set y=0 in the equation:

    2x - 4(0) - 7 = 0

    x =72 \frac{7}{2}​​

    So, x-intercept =(72,0)\left(\frac{7}{2}, 0\right)​​

    Find y-intercept

    Set x=0 in the equation:

    2(0)−4y−7=0

    y = -74\frac{7}{4}​​

    So, y-intercept = (0,74)\left(0, -\frac{7}{4}\right)

    Since we take absolute values for area calculations, we use 74\frac{7}{4}
    74\frac{7}{4}​​​

    Area=12×72×74\text{Area} = \frac{1}{2} \times \frac{7}{2} \times \frac{7}{4}​​

    Area=12×498=4916 \frac{1}{2} \times \frac{49}{8}= \frac{49}{16}

    Option (D) is right.

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