The altitudes of two similar triangles are 4 cm and 6 cm. If the area of the larger triangle is 36 cm? , what will be the area of the other one?

Correct option is A

Given:
Altitudes of two similar triangles are 4 cm and 6 cm
larger triangle is 36 cm
Formula used:
​$$\frac{Area \ of \ the \ larger \ triangle}{Area \ of \ the \ smaller \ triangle }=\frac{(Height \ of \ the \ larger∆)^2}{(Height \ of \ the \ larger∆)^2}$$​​
Solution:
​$$\frac{A1}{A2} = \frac{6^2}{4^2} \\\ \\\frac{36}{A2} = \frac{36}{16}\\\ \\A2 = 16$$

Then the area of smaller triangle = 16 $$cm^2$$​​