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    The ages of two persons differ by 15 years. If 5 years ago, the age of the older person was twice that of the younger one, then their present ages (in
    Question

    The ages of two persons differ by 15 years. If 5 years ago, the age of the older person was twice that of the younger one, then their present ages (in years) are :

    A.

    30, 15

    B.

    20, 5

    C.

    25, 10

    D.

    35, 20

    Correct option is D

    Given:

    Age difference = 15 years

    5 years ago, older person’s age = 2 × younger person’s age at that time

    Solution:

    Let present age of younger person = x
    Then, older person’s age = x + 15
    Five years ago:

    Younger = x - 5

    Older = x + 15 - 5 = x + 10

    From the condition;

    x + 10 = 2(x - 5)

    x + 10 = 2x − 10

    10 + 10 = 2x − x

    x = 20

    So, present ages:

    Younger = 20 years

    Older = 20 + 15 = 35 years

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