The ages of two persons differ by 14 years. If 4 years ago, the elder one was three times as old as the younger one, then the present age of younger one is:
Given:
The difference in the ages of two persons is 14 years.
Four years ago, the elder one was three times as old as the younger one.
Solution:
Let the age of younger one is x years
So, bigger one = x + 14
The condition given is that 4 years ago, the elder's age was three times the younger's age:
x + 14 - 4 = 3(x - 4)
x +10 = 3(x−4)
x+10 = 3x−12
10+12 = 3x−x
22 = 2x
x = 11 years
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