The ages of a father and his son together add up to 80 years. If the age of the son be doubled, it will exceed the father's age by 10 years. Find the present age of the son.
Given:
The sum of ages of father and son = 80 years
If the age of son is doubled then it exceeds age of father by 10
Solution:
Let the age of son be x
Then age of father will be (80-x)
According to question:
2x - (80-x) = 10
2x - 80 + x = 10
3x = 90
x = 30years
The age of son is 30years
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