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    The age of the older of two boys is thrice that of the younger. 9 years ago, it was five times that of the younger. Find the present age of each.
    Question

    The age of the older of two boys is thrice that of the younger. 9 years ago, it was five times that of the younger. Find the present age of each.

    A.

    15 years, 45 years

    B.

    12 years, 36 years

    C.

    17 years, 51 years

    D.

    18 years, 54 years

    Correct option is D

    Given:
    Let the Age of the younger boy be x years,
    The age of older boy is = 3x years.
    9 years ago, their age
    Younger boy = x-9 years.
    Older boy = 3x-9 years.
    Solution:
    (3x-9)=5(x-9)
    3x - 9 = 5x – 45
    -5x + 3x = -45 + 9
    -2x = -36
    2x = 36
    x = 18
    So, the present age of older and younger boys are 54 years and 18 years respectively.
    Alternate Method:
    As per the given question,
    Older younger
    Their present age ratio - 3 : 1
    Ages 9 years ago - 5 :  1
    Difference of their age ratios should be same in both the condition.
    So, the new ration be
    Older younger
    Their present age ratio - 6 :  2
    Ages 9 years ago - 5 : 1
    Difference of present age – old age = 1 unit
    1 unit → 9 year,
    So,
    6 unit → 54 years
    2 unit → 18 years

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