Suppose $$729^ \frac {22}{3}81^\frac {x}{2} = 3$$​ . The value of x is

Correct option is B

Formula used : 
​$$\left(a^m\right)^n = a^{m \cdot n}$$​​
Solution : 
729=$$3^6$$ and 81 = $$3^4$$
Substitute these values into the equation:
​​$$\left(3^6\right)^{\frac{22}{3}} \cdot \left(3^4\right)^{\frac{x}{2}} = 3$$
The equation becomes:
​​$$3^{44} \cdot 3^{2x} = 3$$
x = $$\frac{-43}{2}$$ = -21.5
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