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    Solve the following.If x−1x=3x-\frac{1}{x}=3x−x1​=3​, then x3−1x3=x^3-\frac{1}{x^3}=x3−x31​=​ ?
    Question

    Solve the following.

    If x1x=3x-\frac{1}{x}=3​, then x31x3=x^3-\frac{1}{x^3}= ?

    A.

    18

    B.

    36

    C.

    9

    D.

    27

    Correct option is B

    Given:

    x1x=3x - \frac{1}{x} = 3​​

    We need to find x31x3.x^3 - \frac{1}{x^3}.​​

    Formula Used:

    x31x3=(x1x)3+3(x1x)x^3 - \frac{1}{x^3} = \left( x - \frac{1}{x} \right)^3 + 3 \left( x - \frac{1}{x} \right)​​

    Solution:

    x31x3=(3)3+3×3=27+9=36x^3 - \frac{1}{x^3} = \left( 3 \right)^3 + 3 \times 3 = 27 + 9 =36​​

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