Correct option is BGiven:x−1x=3x - \frac{1}{x} = 3x−x1=3We need to find x3−1x3.x^3 - \frac{1}{x^3}.x3−x31.Formula Used:x3−1x3=(x−1x)3+3(x−1x)x^3 - \frac{1}{x^3} = \left( x - \frac{1}{x} \right)^3 + 3 \left( x - \frac{1}{x} \right)x3−x31=(x−x1)3+3(x−x1)Solution:x3−1x3=(3)3+3×3=27+9=36x^3 - \frac{1}{x^3} = \left( 3 \right)^3 + 3 \times 3 = 27 + 9 =36x3−x31=(3)3+3×3=27+9=36