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Solve the following.If x−1x=3x-\frac{1}{x}=3x−x1​=3​, then x3−1x3=x^3-\frac{1}{x^3}=x3−x31​=​ ?
Question

Solve the following.

If x1x=3x-\frac{1}{x}=3​, then x31x3=x^3-\frac{1}{x^3}= ?

A.

18

B.

36

C.

9

D.

27

Correct option is B

Given:

x1x=3x - \frac{1}{x} = 3​​

We need to find x31x3.x^3 - \frac{1}{x^3}.​​

Formula Used:

x31x3=(x1x)3+3(x1x)x^3 - \frac{1}{x^3} = \left( x - \frac{1}{x} \right)^3 + 3 \left( x - \frac{1}{x} \right)​​

Solution:

x31x3=(3)3+3×3=27+9=36x^3 - \frac{1}{x^3} = \left( 3 \right)^3 + 3 \times 3 = 27 + 9 =36​​

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