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    sin⁡2θ+11+tan⁡2θ=?\sin^2 \theta + \frac{1}{1 + \tan^2 \theta} = ?sin2θ+1+tan2θ1​=?​
    Question

    sin2θ+11+tan2θ=?\sin^2 \theta + \frac{1}{1 + \tan^2 \theta} = ?

    A.

    1

    B.

    -1

    C.

    0

    D.

    None of these

    Correct option is A

    Given:

    sin2θ+11+tan2θ\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}
    Solution:

    (sin2θ+11+tan2θ)\left( \sin^2 \theta + \frac{1}{1 + \tan^2 \theta} \right)

    =(sin2θ+1sec2θ)= \left( \sin^2 \theta + \frac{1}{\sec^2 \theta} \right)

    =(sin2θ+cos2θ)= \left( \sin^2 \theta + \cos^2 \theta \right)

    = 1

    Thus, the correct answer is (a).

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