arrow
arrow
arrow
sin⁡2θ+11+tan⁡2θ=?\sin^2 \theta + \frac{1}{1 + \tan^2 \theta} = ?sin2θ+1+tan2θ1​=?​
Question

sin2θ+11+tan2θ=?\sin^2 \theta + \frac{1}{1 + \tan^2 \theta} = ?

A.

1

B.

-1

C.

0

D.

None of these

Correct option is A

Given:

sin2θ+11+tan2θ\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}
Solution:

(sin2θ+11+tan2θ)\left( \sin^2 \theta + \frac{1}{1 + \tan^2 \theta} \right)

=(sin2θ+1sec2θ)= \left( \sin^2 \theta + \frac{1}{\sec^2 \theta} \right)

=(sin2θ+cos2θ)= \left( \sin^2 \theta + \cos^2 \theta \right)

= 1

Thus, the correct answer is (a).

Free Tests

Free
Must Attempt

BSSC General Awareness Section Test 01

languageIcon English
  • pdpQsnIcon40 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon30 Mins
languageIcon English
Free
Must Attempt

BSSC Office Attendant Full Mock Test : 01

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon400 Marks
  • timerIcon120 Mins
languageIcon English
Free
Must Attempt

संज्ञा

languageIcon English
  • pdpQsnIcon10 Questions
  • pdpsheetsIcon40 Marks
  • timerIcon10 Mins
languageIcon English
test-prime-package

Access ‘Bihar Deled’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
399k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow