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sin⁡2θ+11+tan⁡2θ=?\sin^2 \theta + \frac{1}{1 + \tan^2 \theta} = ?sin2θ+1+tan2θ1​=?​
Question

sin2θ+11+tan2θ=?\sin^2 \theta + \frac{1}{1 + \tan^2 \theta} = ?

A.

1

B.

-1

C.

0

D.

None of these

Correct option is A

Given:

sin2θ+11+tan2θ\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}
Solution:

(sin2θ+11+tan2θ)\left( \sin^2 \theta + \frac{1}{1 + \tan^2 \theta} \right)

=(sin2θ+1sec2θ)= \left( \sin^2 \theta + \frac{1}{\sec^2 \theta} \right)

=(sin2θ+cos2θ)= \left( \sin^2 \theta + \cos^2 \theta \right)

= 1

Thus, the correct answer is (a).

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