Simplify$$\frac{(x^2-9)}{(x+3)}$$​

Correct option is B

Given:

​$$\frac{(x^2-9)}{(x+3)}$$​​

Formula Used:

​$$a^2 - b^2 = (a - b)(a + b)$$​​

Solution:

​$$\frac{(x^2-9)}{(x+3)}$$​​

​$$=\frac{(x+3)(x-3)}{(x+3)}$$​​

​$$=(x-3)$$​​