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    Simplify the following. ​[(1−12)(1−13)(1−14)⋯(1−1100)]−0.5\left[ \left(1 - \frac{1}{2}\right)\left(1 - \frac{1}{3}\right)\left(1 - \frac{1}{4}\ri
    Question

    Simplify the following. 
    [(112)(113)(114)(11100)]0.5\left[ \left(1 - \frac{1}{2}\right)\left(1 - \frac{1}{3}\right)\left(1 - \frac{1}{4}\right) \cdots \left(1 - \frac{1}{100}\right) \right]^{-0.5}​​

    A.

    1100\frac{1}{100}

    B.

    110\frac 1{10}

    C.

    100

    D.

    10

    Correct option is D

    Given:
    [(112)(113)(114)(11100)]0.5\left[ \left(1 - \frac{1}{2}\right)\left(1 - \frac{1}{3}\right)\left(1 - \frac{1}{4}\right) \cdots \left(1 - \frac{1}{100}\right) \right]^{-0.5}​​
    Formula Used:
    The formula used for simplifying the individual terms is:
    11n=n1n1 - \frac1n = \frac{n - 1}n​​
    Solution:
    =[(112)(113)(114)(11100)]0.5 =[(212)(313)(414)(1001100)]0.5= \left[ \left(1 - \frac{1}{2}\right)\left(1 - \frac{1}{3}\right)\left(1 - \frac{1}{4}\right) \cdots \left(1 - \frac{1}{100}\right) \right]^{-0.5} \\\ \\ = \left[ \left( \frac{2-1}{2}\right)\left( \frac{3-1}{3}\right)\left( \frac{4-1}{4}\right) \cdots \left(\frac{100- 1 }{100}\right) \right]^{-0.5}​​​
    =[(12)×(23)×(34)××(99100)]0.5=(1100)0.5=100=10= \left[ \left( \frac{1}{2} \right) \times \left( \frac{2}{3} \right) \times \left( \frac{3}{4} \right) \times \cdots \times \left( \frac{99}{100} \right) \right]^{-0.5}\\= \left( \frac{1}{100} \right)^{-0.5}\\ = \sqrt{100} = 10




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