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Simplify the expression: sinA+cosAtan(90−A)sin A + \frac{cos A}{tan(90-A)}sinA+tan(90−A)cosA​​​
Question

Simplify the expression: sinA+cosAtan(90A)sin A + \frac{cos A}{tan(90-A)}​​

A.

2 cosecA

B.

cotA

C.

2 sinA

D.

tanA

Correct option is C

Given:

sinA+cosAtan(90A)sin A + \frac{cos A}{tan(90-A)}

Concept Used:

tan (90 -A) = cot A

cot A = cosAsinA\frac{cos A}{sinA}

Solution:

sinA+cosAtan(90A)sin A + \frac{cos A}{tan(90-A)}

=sinA+cosAcotAsin A + \frac{cos A}{cotA}

=sinA+cosAcosAsinAsin A + \frac{cos A}{\frac{cosA}{sinA}}

=sin A + sin A= 2 sinA

Thus ,option (c) is right.

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