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Simplify: sin⁡θ1−cos⁡θ\frac{\sin \theta}{1-\cos\theta}1−cosθsinθ​​​
Question

Simplify: sinθ1cosθ\frac{\sin \theta}{1-\cos\theta}​​

A.

cosecθ + cot⁡θ

B.

tanθsecθ\tan\theta-\sec\theta

C.

tanθ+secθ\tan\theta+\sec\theta​​

D.

cosecθ - cot⁡θ

Correct option is A

Given:
The expression to simplify: sinθ1cosθ\frac{\sin \theta}{1-\cos\theta}
Solution:
multiplying by 1+cosθ1+cosθ\frac{1+cos\theta}{1+cos\theta}​​
=sinθ1cosθ×1+cosθ1+cosθ =sinθ(1+cosθ)(1cosθ)(1+cosθ) =sinθ(1+cosθ)sin2θ =(1+cosθ)sinθ =1sinθ+cosθsinθ =cosecθ+cotθ=\frac{\sin \theta}{1-\cos\theta}\times\frac{1+cos\theta}{1+cos\theta} \\ \ \\ =\frac{sin\theta(1+cos\theta)}{(1-cos\theta)(1+cos\theta)}\\ \ \\ =\frac{sin\theta(1+cos\theta)}{\sin^2\theta}\\ \ \\ =\frac{(1+cos\theta)}{\sin\theta}\\ \ \\ =\frac{1}{\sin\theta}+\frac{\cos\theta}{\sin\theta}\\ \ \\ =\cosec\theta + \cot\theta
​​
​​
sin⁡θ1−cos⁡θ\frac{\sin \theta}{1 - \cos \theta}
​​​

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