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    Simplify: sin⁡θ1−cos⁡θ\frac{\sin \theta}{1-\cos\theta}1−cosθsinθ​​​
    Question

    Simplify: sinθ1cosθ\frac{\sin \theta}{1-\cos\theta}​​

    A.

    cosecθ + cot⁡θ

    B.

    tanθsecθ\tan\theta-\sec\theta

    C.

    tanθ+secθ\tan\theta+\sec\theta​​

    D.

    cosecθ - cot⁡θ

    Correct option is A

    Given:
    The expression to simplify: sinθ1cosθ\frac{\sin \theta}{1-\cos\theta}
    Solution:
    multiplying by 1+cosθ1+cosθ\frac{1+cos\theta}{1+cos\theta}​​
    =sinθ1cosθ×1+cosθ1+cosθ =sinθ(1+cosθ)(1cosθ)(1+cosθ) =sinθ(1+cosθ)sin2θ =(1+cosθ)sinθ =1sinθ+cosθsinθ =cosecθ+cotθ=\frac{\sin \theta}{1-\cos\theta}\times\frac{1+cos\theta}{1+cos\theta} \\ \ \\ =\frac{sin\theta(1+cos\theta)}{(1-cos\theta)(1+cos\theta)}\\ \ \\ =\frac{sin\theta(1+cos\theta)}{\sin^2\theta}\\ \ \\ =\frac{(1+cos\theta)}{\sin\theta}\\ \ \\ =\frac{1}{\sin\theta}+\frac{\cos\theta}{\sin\theta}\\ \ \\ =\cosec\theta + \cot\theta
    ​​
    ​​
    sin⁡θ1−cos⁡θ\frac{\sin \theta}{1 - \cos \theta}
    ​​​

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