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    Simplify: cos(30° - A) - cos(30° + A)
    Question

    Simplify: cos(30° - A) - cos(30° + A)

    A.

    cos A

    B.

    (1/2) sin A

    C.

    sin A

    D.

    2sinA

    Correct option is C

    Given: 
    cos(30° - A) - cos(30° + A) 
    Formula Used:cos(xy)=cosxcosy+sinxsinycos(x+y)=cosxcosysinxsinySolution:cos(30A)=cos30cosA+sin30sinAcos(30+A)=cos30cosAsin30sinAThus solving,cos(30A)cos(30+A)=cos30×cosA+sin30×sinAcos30×cosA+sin30×sinAcos(30A)cos(30+A)=2×sin30×sinAcos(30A)cos(30+A)=2×12×sinAcos(30A)cos(30+A)=sinA\textbf{Formula Used:}\\\cos(x - y) = \cos x \cos y + \sin x \sin y \\\cos(x + y) = \cos x \cos y - \sin x \sin y \\\textbf{Solution}: \\\cos(30^\circ - A) = \cos 30^\circ \cos A + \sin 30^\circ \sin A \\\cos(30^\circ + A) = \cos 30^\circ \cos A - \sin 30^\circ \sin A \\\\\text{Thus solving,} \\\\\cos(30^\circ - A) - \cos(30^\circ + A) = \cos 30^\circ \times \cos A + \sin 30^\circ \times \sin A - \cos 30^\circ \times \cos A + \sin 30^\circ \times \sin A \\\cos(30^\circ - A) - \cos(30^\circ + A) = 2 \times \sin 30^\circ \times \sin A \\\cos(30^\circ - A) - \cos(30^\circ + A) = 2 \times \frac{1}{2} \times \sin A \\\cos(30^\circ - A) - \cos(30^\circ + A) = \sin A​​














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