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Simplify:​(1−sec2θ)(1−sinθ)(1+sinθ)(1+cot2θ)(1 - sec^2\theta)(1 - sin\theta)(1 + sin\theta)(1 + cot^2\theta)(1−sec2θ)(1−sinθ)(1+sinθ)(1+cot2θ)
Question

Simplify:

(1sec2θ)(1sinθ)(1+sinθ)(1+cot2θ)(1 - sec^2\theta)(1 - sin\theta)(1 + sin\theta)(1 + cot^2\theta)

A.

2

B.

-1

C.

0

D.

1

Correct option is B

Given: 

(1sec2θ)(1sinθ)(1+sinθ)(1+cot2θ)(1 - \sec^2\theta)(1 - \sin\theta)(1 + \sin\theta)(1 + \cot^2\theta) 

Formula Used: 

sec2θ=1+tan2θ 1+cot2θ=cosec2θ (1sinθ)(1+sinθ)=1sin2θ=cos2θ tanθ=sinθcosθ\sec^2\theta = 1 + \tan^2\theta \\ \ \\1 + \cot^2\theta = \cosec^2\theta\\ \ \\(1 - \sin\theta)(1 + \sin\theta) = 1 - \sin^2\theta = \cos^2\theta \\ \ \\\tan\theta = \frac{\sin\theta}{\cos\theta}

Solution: 

(1sec2θ)(1sinθ)(1+sinθ)(1+cot2θ)  =(1sec2θ)(1sin2θ)(1+cot2θ) =(tan2θ)(cos2θ)(sec2θ)  =(sin2θcos2θ)(cos2θ)(1sin2θ) =1(1 - \sec^2\theta)(1 - \sin\theta)(1 + \sin\theta)(1 + \cot^2\theta) \\\ \ \\ = (1 - \sec^2\theta)(1 - \sin^2\theta)(1 + \cot^2\theta)\\ \ \\ = (- \tan^2\theta)(\cos^2\theta)(\sec^2\theta)\\ \ \\\ = -\left(\frac{\sin^2\theta}{\cos^2\theta}\right)(\cos^2\theta)\left(\frac{1}{\sin^2\theta}\right) \\ \ \\ = -1​​

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