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Simplify 1+cosA1−cosA\sqrt\frac{1+cosA}{1-cosA}1−cosA1+cosA​​​
Question

Simplify 1+cosA1cosA\sqrt\frac{1+cosA}{1-cosA}

A.

sec⁡A+tan⁡A

B.

sec⁡A-tan⁡A

C.

cosec⁡A+cot⁡A

D.

cosec⁡A-cot⁡A

Correct option is C

Given:

1+cosA1cosA\sqrt\frac{1+cosA}{1-cosA}

Concept:

1sinA\frac{1}{sinA} = cosec A

cosAsinA\frac{cosA}{sin A} = cot A

Solution:

1+cosA1cosA\sqrt\frac{1+cosA}{1-cosA}

We multiply both the numerator and the denominator by 1+ cosA

(1+cosA)2(1cosA)(1+cosA)\sqrt\frac{(1+cosA)^2}{(1-cosA)(1+cosA)}

​​The denominator is now a difference of squares:

(1−cosA) (1+cosA) = 12cos2A=sin2A1^2 - cos^2A = sin^2A

​​(1+cosA)2sin2A\sqrt\frac{(1+cosA)^2}{sin^2A}

1+cosAsinA\frac{1+cosA}{sinA}

1sinA+cosAsinA\frac{1}{sinA}+\frac{cosA}{sinA}

cosecA + cotA

1+cos⁡A1 + \cos AThus, the correct option is (c) cosecA + cotA


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