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    Pranav borrows a sum of ₹335180 at the rate of 13% per annum simple interest. At the end of the first year, he repays ₹23060 towards return of princip
    Question

    Pranav borrows a sum of ₹335180 at the rate of 13% per annum simple interest. At the end of the first year, he repays ₹23060 towards return of principal amount borrowed. If Pranav clears all pending dues at the end of the second year, including interest payment that accrued during the first year, how much does he pay (in ₹) at the end of the second year? 

    A.

    398876

    B.

    393949

    C.

    396269

    D.

    388076

    Correct option is C

    Given:

    Principal borrowed by Pranav: ₹335,180
    Rate of interest: 13% per annum (Simple Interest)
    Repayment towards principal at the end of the first year: ₹23,060
    Pranav clears all dues, including interest, at the end of the second year.
    Formula Used:

    Simple interest is calculated using the formula:
    SI=P×R×T100\text{SI} = \frac{P \times R \times T}{100}​​
    Where (P) is the principal amount, (R) is the rate of interest, and (T) is the time in years.
    Solution:

    The interest for the first year:
    SI =335180×13×1100=43,573.40 = \frac{335180 \times 13 \times 1}{100} = 43,573.40​​
    the first year, Pranav repays ₹23,060 towards the principal. So, the new principal at the start of the second year is:
    Remaining principal = 335180 - 23060 = 312120

    The interest for the second year with the new principal:
    SI for the second year= 312120×13×1100=40,575.60\frac{312120 \times 13 \times 1}{100} = 40,575.60
    Pranav needs to pay the remaining principal and the interest for both the first and second years:
    Total payment} = 312120 + 43573.40 + 40575.60 = 396,269
    Pranav will pay ₹396,269 at the end of the second year.

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