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    The simple interest on a certain sum for 4294\frac{2}{9}492​​ years at the rate of 4.5% per annum is ₹8,778. What will be the amount payable on t
    Question

    The simple interest on a certain sum for 4294\frac{2}{9}​ years at the rate of 4.5% per annum is ₹8,778. What will be the amount payable on the same sum at the rate of 5.5% per annum simple interest in 2572\frac{5}{7}​ years?

    A.

    ₹53,091

    B.

    ₹53,089

    C.

    ₹53,097

    D.

    ₹53,083

    Correct option is C

    Given:Simple Interest on a certain sum for 429 years at 4.5% p.a. =8,778Rate for second case =5.5% p.a.Time for second case =257 yearsFormula Used:SI=P×R×T100A=P+SISolution:429=3894.5%=92%8778=P×92×3891008778=P×382008778=19P100P=8778×10019P=46,2005.5%=112%257=197SI=46200×112×197100SI=46200×11×191400SI=6,897A=P+SIA=46,200+6,897A=53,09753,097\textbf{Given:}\\\text{Simple Interest on a certain sum for }4\frac{2}{9}\text{ years at }4.5\%\text{ p.a. }= ₹8,778\\\text{Rate for second case }=5.5\%\text{ p.a.}\\\text{Time for second case }=2\frac{5}{7}\text{ years}\\[1em]\textbf{Formula Used:}\\\\SI=\frac{P\times R\times T}{100}\\A=P+SI\\[1em]\textbf{Solution:}\\4\frac{2}{9}=\frac{38}{9}\\\qquad\\4.5\%=\frac{9}{2}\%\\[1em]8778=\frac{P\times \frac{9}{2}\times \frac{38}{9}}{100}\\[1em]8778=\frac{P\times 38}{200}\\[1em]8778=\frac{19P}{100}\\[1em]P=\frac{8778\times 100}{19}\\[1em]P=46,200\\[2em]5.5\%=\frac{11}{2}\%\qquad2\frac{5}{7}=\frac{19}{7}\\[1em]SI=\frac{46200\times \frac{11}{2}\times \frac{19}{7}}{100}\\[1em]SI=\frac{46200\times 11\times 19}{1400}\\[1em]SI=6,897\\[2em]A=P+SI\\[1em]A=46,200+6,897\\[1em]A=53,097\\[2em]\boxed{₹53,097}​​

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