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    P, Q and R together have 180 candies among them. P gives Q and R each as many candies as they already have. After this, R gives Q half as many candies
    Question

    P, Q and R together have 180 candies among them. P gives Q and R each as many candies as they already have. After this, R gives Q half as many candies as Q already has, and R also gives P twice as many candies as P already has. Now each of them has the same number of candies with them. What is the ratio of the respective number of candies P and R had initially?

    A.

    3 : 2

    B.

    2 : 1

    C.

    1 : 2

    D.

    5 : 3

    Correct option is D

    Given:
    P, Q and R together have 180 candies
    P gives Q and R each as many candies as they already have.
    R gives Q half as many candies as Q already has.
    R also gives twice as many candies as P already has.
    At last each of them has the same number of candies with them.
    Solution:
    Let the number of candies P, Q and R have be 'p', 'q' and 'r' respectively.
    According to the question,
    P gives Q and R each as many candies as they already have.
    => Candies left with Q = q + q = 2q
    => Candies left with R = r + r = 2r
    => Candies left with P = p - q - r
    R gives Q half as many candies as Q already has
    => Candies left with Q = 2q + q = 3q
    => Candies left with R = 2r - q
    R also gives twice as many candies as P already has
    => Candies left with P = (p - q - r) + 2(p - q - r) = 3(p - q - r)
    => Candies left with R = (2r - q) - 2(p - q - r) = 4r + q - 2p
    At last each of them has the same number of candies with them
    Number of candies left with P = Number of candies left with Q
    => 3(p - q - r) = 3q
    => 3(p - r) = 6q
    => p - r = 2q ....(i)
    Number of candies left with R = Number of candies left with Q
    => 4r + q - 2p = 3q
    => 4r - 2p = 2q ....(ii)
    Equating equation (i) and (ii)
    => p - r = 4r - 2p
    => 3p = 5r
    => pr=53\frac pr = \frac 53​= 5 : 3

    ∴ The ratio of the respective number of candies P and R had initially was 5 : 3
    Alternate Solution:
    Let the number of candies P, Q and R have after last sharing be 60, 60 and 60.
    Before last sharing,
    => Candies with P, Q and R was = 20 : 40 : 120
    Initial ratio
    => Candies with P, Q and R was = 100 : 20 : 60
    => Ratio of candies with P and R = 10060\frac{100}{60}​ = 5 : 3
    ∴ The ratio of the respective number of candies P and R had initially was 5 : 3

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