Mr. kumar drives to work at an average speed of 48 km per hour. The time taken to cover the first 60% of the distance is 10 minutes more than the time taken to cover the remaining distance. How far is his office?

​​Given:

The first 60% of the distance is 0.6D

The remaining 40% of the distance is 0.4D

Mr. Kumar's speed is 48 km/h.

The time taken to cover the first 60% is 10 minutes more than the time taken to cover the remaining distance.

Time = Distance / Speed.
Time to cover the first 60% of the distance:

Time1=$$\frac{0.6D}{48}$$​​

Time to cover the remaining 40% of the distance:

Time2= $$\frac{0.4D}{48}$$ 

Time1 = Time2  + $$\frac{1}{6}$$ 

​$$\frac{0.6D}{48} = \frac{0.4D}{48} + \frac{1}{6}$$ 

0.6D = 0.4D + 8
0.6D - 0.4D = 8
0.2D = 8
D = $$\frac{8} {0.2}$$​​

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