Manish fixed 48 poles in order to fence a square. If the distance between 2 poles is 5 m, then what will be the area of the square, formed?

Total poles used = 48

Distance between two consecutive poles = 5 meters

In a square fence, poles are placed along all four sides. Since the four corner poles are counted once per side, the number of intervals (spaces) between poles along the perimeter is 48.

Perimeter of the square = (Number of poles) × (Distance between poles)

Side of the square = $$\frac{\text{Perimeter}}{4}$$​​

Area of the square = $$(\text{Side})^2$$​​

Calculating the perimeter:

Perimeter = 48 × 5 = 240 meters

Now,

Side = $$\frac{240}{4}$$​ = 60 meters

So, the area:

Area = $$60^2$$​ = 3600 square meters

Thus, The area of the square is 3600 square meters.