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    Let ABC, PQR be two congruent triangles such that angle A = angle P = 90°. If BC = 13cm, PR = 5cm, find AB.
    Question

    Let ABC, PQR be two congruent triangles such that angle A = angle P = 90°. If BC = 13cm, PR = 5cm, find AB.

    A.

    12 cm

    B.

    8 cm

    C.

    10 cm

    D.

    5 cm

    Correct option is A

    Given:
    - ABC\triangle ABC  and  PQR \triangle PQR​ are congruent right-angled triangles.
    -  A=P=90\angle A = \angle P = 90^\circ
    - Hypotenuse   BC = 13 cm 
    - Side PR = 5cm 
    Theorem  Used:

    - Pythagoras theorem:

    In a right-angled triangle, Hypotenuse2=Base2+Height2\text{In a right-angled triangle, } \text{Hypotenuse}^2 = \text{Base}^2 + \text{Height}^2​​
    Solution:


    Since ABC and PQR \triangle ABC \ and \ \triangle PQR ​ are congruent, corresponding sides are equal. So,  BC = QR = 13 cm  and  PR = AB 

    Applying the Pythagoras theorem in PQR \triangle PQR​:

    QR2=PQ2+PR2QR^2 = PQ^2 + PR^2​​
    Substitute the known values:
    132=PQ2+5213^2 = PQ^2 + 5^2​​
    169=PQ2+25169 = PQ^2 + 25​​
    PQ2=16925=144PQ^2 = 169 - 25 = 144​​
    PQ=144=12PQ = \sqrt{144} = 12​​
    Therefore,  AB = 12 cm


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