Let a set S = {1, 2, 2, 3, 3,3, 4, 4,4, 4}. Then the value of 4 × mean + 2 × mode - 8 × median is:

Correct option is C

Given:
Set S = {1, 2, 2, 3, 3,3, 4, 4, 4, 4} 

Formula Used:
Mean =$$\frac{Sum \ of \ values}{n}$$ ,

Mode = Most frequent term 

For even terms, n:

Median = $$\frac{\text{Value at position } \frac{n}{2} + \text{Value at position } (\frac{n}{2} + 1)}{2}$$​​

Solution:
Mean =$$\frac{1+2+2+3+3+3+4+4+4+4}{10} = \frac{30}{10} = 3$$​
Mode = 4 (most frequent),

Median = $$\frac{3 + 3}{2} = 3$$​
Value = $$4 \times 3 + 2 \times 4 - 8 \times 3 = 12 + 8 - 24 = \bf -4$$​