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    If the mode of the following data is 125, then what is the value of x? Class 110-115 115-120 120-125 125-130 130-135 Frequency 13
    Question

    If the mode of the following data is 125, then what is the value of x?

    Class

    110-115

    115-120

    120-125

    125-130

    130-135

    Frequency

    13

    31

    39

    x

    15

    A.

    48

    B.

    40

    C.

    31

    D.

    39

    Correct option is D

    Given:

    The mode of the data is 125, and the frequencies for the classes are provided. We need to find the value of x

    Concept Used:

    To calculate the mode of a grouped frequency distribution, the formula is:

    Mode = L + f1f02f1f0f2×h\frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h​​

    Where:

    L is the lower boundary of the modal class

    f1f_1​ is the frequency of the modal class

    f0f_0​ is the frequency of the class before the modal class

    f2f_2​ is the frequency of the class after the modal class

    h is the class width 

    Solution: 

    125=120+(3931)(2(39)31x)×5 125=120+8(7831x)×5 125=120+8(47x)×5 125120=8×5(47x) 5=40(47x) 5×(47x)=40 2355x=40 23540=5x 195=5x x=1955 x=39125 = 120 + \frac{(39 - 31)}{(2(39) - 31 - x)} \times 5 \\\ \\125 = 120 + \frac{8}{(78 - 31 - x)} \times 5\\\ \\125 = 120 + \frac{8}{(47 - x)} \times 5\\\ \\125 - 120 = \frac{8 \times 5}{(47 - x)}\\\ \\5 = \frac{40}{(47 - x)}\\\ \\5 \times (47 - x) = 40\\\ \\235 - 5x = 40\\\ \\235 - 40 = 5x\\\ \\195 = 5x\\\ \\x = \frac{195}{5}\\\ \\x = 39​​
    Thus, the value of x is 39.


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