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If the mode of the following data is 125, then what is the value of x? Class 110-115 115-120 120-125 125-130 130-135 Frequency 13
Question

If the mode of the following data is 125, then what is the value of x?

Class

110-115

115-120

120-125

125-130

130-135

Frequency

13

31

39

x

15

A.

48

B.

40

C.

31

D.

39

Correct option is D

Given:

The mode of the data is 125, and the frequencies for the classes are provided. We need to find the value of x

Concept Used:

To calculate the mode of a grouped frequency distribution, the formula is:

Mode = L + f1f02f1f0f2×h\frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h​​

Where:

L is the lower boundary of the modal class

f1f_1​ is the frequency of the modal class

f0f_0​ is the frequency of the class before the modal class

f2f_2​ is the frequency of the class after the modal class

h is the class width 

Solution: 

125=120+(3931)(2(39)31x)×5 125=120+8(7831x)×5 125=120+8(47x)×5 125120=8×5(47x) 5=40(47x) 5×(47x)=40 2355x=40 23540=5x 195=5x x=1955 x=39125 = 120 + \frac{(39 - 31)}{(2(39) - 31 - x)} \times 5 \\\ \\125 = 120 + \frac{8}{(78 - 31 - x)} \times 5\\\ \\125 = 120 + \frac{8}{(47 - x)} \times 5\\\ \\125 - 120 = \frac{8 \times 5}{(47 - x)}\\\ \\5 = \frac{40}{(47 - x)}\\\ \\5 \times (47 - x) = 40\\\ \\235 - 5x = 40\\\ \\235 - 40 = 5x\\\ \\195 = 5x\\\ \\x = \frac{195}{5}\\\ \\x = 39​​
Thus, the value of x is 39.


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