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Lavanya got married 10 years ago. Now her age is 115\frac{1}{5}51​​​times her age at the time of marriage. Her son's present age is one-tenth of her p
Question

Lavanya got married 10 years ago. Now her age is 115\frac{1}{5}​​times her age at the time of marriage. Her son's present age is one-tenth of her present age. Find her son's present age.

A.

6 years

B.

5 years

C.

​20 years

D.

12 years

Correct option is A

Given:

- Lavanya got married 10 years ago.

- Her present age is 1151 \frac{1}{5}​  times  her age at the time of marriage.

- Her son's present age is one-tenth of her present age.

Solution:

Let Lavanya's age at the time of marriage be x years.
Then her present age = x + 10.
According to the question, present age = 65×x\frac{6}{5} \times x​​

x+10=(65)×xx + 10 = (\frac{6}{5}) \times x​​

5(x + 10) = 6x

5x + 60 = 6x

50 = 6x - 5x

50 = x

x = 50

So, Lavanya's present age = 50 + 10 = 60 years

Her son's age = 60×110\times\frac{1}{10}  = 6 years

Lavanya's son's present age is 6  years.

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