John is twice as old as Jean. After 3 years, the sum of their ages will be 66 years. What are the present ages of Jean and John, respectively?
Given:
John is twice as old as Jean
After 3 years, the sum of their ages = 66 years
Solution:
Let Jean's present age be x years
Then John's present age = 2x years
After 3 years:
Jean's age = x + 3
John's age = 2x + 3
Sum of their ages = 66
(x + 3) + (2x + 3) = 66
3x + 6 = 66
3x = 66 - 6 = 60
x = = 20
Jean's present age = x = 20 years
John's present age = 2x = 40 years
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