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In △XYZ, right angled at Y, if sin X=1/2, find the value of cos X cos Z+sin X sin Z.
Question

In △XYZ, right angled at Y, if sin X=1/2, find the value of cos X cos Z+sin X sin Z.

A.

√3/2

B.

√3/4

C.

2/√3

D.

√3

Correct option is A

Given: 

△XYZ, right angled at Y. 

sinx=12\sin x = \frac{1}{2} 

Formula Used:  

sin300=12\sin 30^0 = \frac{1}{2} 

cos300=32\cos 30^0 = \frac{\sqrt{3}}{2} 

cos(xz)=cosxcosz+sinxsinz\cos ( x - z ) = \cos x \cos z + sin x \sin z 

Solution:

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