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    In △XYZ, right angled at Y, if sin X=1/2, find the value of cos X cos Z+sin X sin Z.
    Question

    In △XYZ, right angled at Y, if sin X=1/2, find the value of cos X cos Z+sin X sin Z.

    A.

    √3/2

    B.

    √3/4

    C.

    2/√3

    D.

    √3

    Correct option is A

    Given: 

    △XYZ, right angled at Y. 

    sinx=12\sin x = \frac{1}{2} 

    Formula Used:  

    sin300=12\sin 30^0 = \frac{1}{2} 

    cos300=32\cos 30^0 = \frac{\sqrt{3}}{2} 

    cos(xz)=cosxcosz+sinxsinz\cos ( x - z ) = \cos x \cos z + sin x \sin z 

    Solution:

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