Correct option is D
The correct answer is
(d).
Explanation: In all the circuits provided, the brightness of the bulb depends on the
current flowing through it, which in turn depends on the
voltage provided by the batteries and the
total resistance in the circuit. · In circuits
(a) and
(c), there is
one battery in the circuit, so the voltage is limited. · In circuits
(b) and
(d), there are
two batteries connected in series, providing
double the voltage to the circuit compared to the circuits with one battery. · However, in
(b), there are two bulbs connected in series. When resistances (bulbs) are connected in series, the total resistance of the circuit increases, and this reduces the current for a given voltage. The brightness of each bulb is less because the voltage is shared between the two bulbs. · In
(d), there are two batteries (higher voltage) but only
one bulb. With a higher voltage and only one bulb, the current is maximized, and the bulb glows the brightest. Thus,
circuit (d) will make the bulb glow the most due to the higher voltage from the two batteries and the absence of additional resistance from a second bulb.
would glow the most? (Consider all batteries are the same)


