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    In triangle DEF, side EF is produced to G. If ∠DFG\angle DFG∠DFG​ = 110° and EF = DF, then ∠DEF\angle DEF∠DEF​ measures:
    Question

    In triangle DEF, side EF is produced to G. If DFG\angle DFG​ = 110° and EF = DF, then DEF\angle DEF​ measures:

    A.

    40o40^o​​

    B.

    70o70^o​​

    C.

    55o55^o​​

    D.

    45o45^o​​

    Correct option is C

    Given:

    In DEF\triangle DEF​, EF= DF

    If EF is produced to G then DFG=110o\angle DFG = 110^o​​

    Formula Used:

    Sum of triangle = 180o180^o​​

    Exterior angle = Sum of interior opposite angles

    Solution:

    In DEF,\triangle DEF,​ EF =DF then D=E \angle D = \angle E​    (Angles opposite to equal sides are equal)

    If EDF=DEF=x \angle EDF = \angle DEF = x ​ then

    EDF+DEF=110o\angle EDF +\angle DEF = 110^o ​      (Exterior angle = Sum of interior opposite angles)

    x+x=110ox + x = 110^o 

    x=55ox= 55^o​​

    DEF=55o\angle DEF = 55^o​​

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