In △PQR,∠PQR = $$90^∘$$,PQ =3 cm and PR = 6 cm. What is the measure of ∠PRQ ?

Correct option is D

Given:

PQ = 3cm

PR = 6cm 

Formula Used: 

​$$\sin \theta = \frac{\text{Perpendicular}}{\text{Base}}$$ 

$$\sin 30\degree = \frac{1}{2}$$​​

Solution:

We use the trigonometric ratio Sin for the angle ∠ PRQ:

sin(∠PRQ) = $$\frac{PQ}{PR}$$ = $$\frac{3}{6}$$ = $$\frac{1}{2}$$​​

∠PQR = $$30\degree$$​​

The angle whose sin value $$\frac{1}{2}$$​  is $$30^∘$$

Thus the correct answer is (D)