In triangle ABC, if the angles are in the ratio 4 : 3 : 5, find the angles.

Correct option is D

Given: 

The angles of triangle $ABC$ are in the ratio $4:3:5$, we can express the angles = 4x , 3x, 5x 

Concept Used:

The sum of the angles in any triangle = $$180\degree$$ 

Solution : 

4x + 3x + 5x = $$180\degree$$ 

12x = $$180\degree$$​​
 x = $$\frac{180\degree}{12}$$ 

x = $$15\degree$$ 

Now, 

First angle 4x = 4 $$\times$$ $$15\degree$$​ = $$60\degree$$ 

Second angle 3x = 3 $$\times$$ $$15\degree$$​ = $$45\degree$$ 

Third angle 5x = 5 $$\times$$ $$15\degree$$ = $$75\degree$$ 

​Thus, the angles of triangle$ABC$ are 

$$60\degree$$, $$45\degree$$, $$75\degree$$​

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