In two triangle ABC and DEF, if $$\bar{AB} = \bar{EF} , \bar{BC} = \bar{DF} \space and \space \bar{CA} = \bar{DE}, \space then:$$​​

Correct option is D

Given:

​$$\overline{AB} = \overline{EF}\\ \ \\\overline{BC} = \overline{DF} \\ \ \\\overline{CA} = \overline{DE}$$

These conditions suggest that the corresponding sides of triangles ABC and DEF are equal.

Concept Used:

If the corresponding sides of two triangles are equal, then the triangles are congruent by the SSS (Side-Side-Side) congruency.

Solution:

Since $$\overline{AB} = \overline{EF}$$​,  $$\overline{BC} = \overline{DF}$$​, and  $$\overline{CA} = \overline{DE}$$​, all corresponding sides of triangle ABC and triangle DEF are equal.

Therefore, by the SSS congruence, we can conclude that:

△CBA ≅ △DFE