Three angles A, B and C of a triangle are in parallel series and AM is perpendicular to BC. What will be the value of BM/AB ?

Correct option is C

Given:

Three angles A, B and C of a triangle are in parallel series and AM is perpendicular to BC.

Solution:

Let ABC is equilateral triangle and his side is a.

All angle is $$60\degree$$.​

So,

​$$\frac{BM}{AB} = \frac{\frac{a}{2}}{a} = \frac{a}{2} \times \frac{1}{a} = \frac{1}{2}$$

Thus, the correct answer is (c).