In triangle ABC, AB = 3 m, BC = 4 m, and  AC = 5 m. In triangle PRQ, PR = 4 m, PQ = 5 m, and RQ = 3 m. Which of the following is a correct order of congruency?

Correct option is D

Given: 

Triangle ABC:
$AB=3\text{m},BC=4\text{m},AC=5\text{m}$

Triangle PRQ:
$PR=4\text{m},PQ=5\text{m},RQ=3\text{m }$

Concept Used: 

SSS Congruence Criterion:

Two triangles are congruent if their corresponding side lengths are equal.

Solution:

Matching the side:

$AB=3\text{m}$ matches $RQ=3\text{m}$

$BC=4\text{m}$ matches $PR=4\text{m}$

$AC=5\text{m}$ matches $PQ=5\text{m}$

The corresponding sides of the two triangles are equal.

Therefore, the two triangles are congruent by SSS Congruence.

Thus, the correct order of congruency is:

$$△BCA\cong △RPQ$$

So the correct answer is (d)

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