Correct option is D
∠BDC + ∠CDA= 180°
76° +∠CDA =180°
∠CDA = 104°
Now,
∠DCA = ∠DAC = 76°/2 = 38°
In BDC,
∠CDB + ∠DBC + ∠DCB = 180°
76° + ∠CBD + 38° = 180°
∠CBD = 66°
In the given triangle, CD is the bisector of ∠BCA. CD = DA. If ∠BDC = 76°, what is the degree measure of ∠CBD?

∠BDC + ∠CDA= 180°
76° +∠CDA =180°
∠CDA = 104°
Now,
∠DCA = ∠DAC = 76°/2 = 38°
In BDC,
∠CDB + ∠DBC + ∠DCB = 180°
76° + ∠CBD + 38° = 180°
∠CBD = 66°
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