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    In the given triangle, CD is the bisector of ∠BCA. CD = DA. If ∠BDC = 76°, what is the degree measure of ∠CBD?
    Question

    In the given triangle, CD is the bisector of ∠BCA. CD = DA. If ∠BDC = 76°, what is the degree measure of ∠CBD?

    A.

    32°

    B.

    76°

    C.

    80°

    D.

    66°

    Correct option is D

    ∠BDC + ∠CDA= 180°
    76° +∠CDA =180°
    ∠CDA = 104°
    Now,
    ∠DCA = ∠DAC = 76°/2 = 38°
    In BDC,
    ∠CDB + ∠DBC + ∠DCB = 180°
    76° + ∠CBD + 38° = 180°
    ∠CBD = 66°

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