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In the given figure, ' G ' is the centre of the circle. Find the angle ACB when ∠AGB=132°\angle AGB = 132\degree∠AGB=132°​​
Question

In the given figure, ' G ' is the centre of the circle. Find the angle ACB when AGB=132°\angle AGB = 132\degree​​

A.

62o

B.

66o

C.

64o

D.

60o

Correct option is B

Given: 

AGB=132°\angle AGB = 132\degree 

Concept Used: 

In a circle , Angle made on the center is two time the angle made on the circumference by the same arc.

Solution: 

ACB=AGB2=1322=66°\angle ACB = \frac{\angle AGB}{2} = \frac{132}{2} = 66\degree​​

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