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    In the given figure, ' G ' is the centre of the circle. Find the angle ACB when ∠AGB=132°\angle AGB = 132\degree∠AGB=132°​​
    Question

    In the given figure, ' G ' is the centre of the circle. Find the angle ACB when AGB=132°\angle AGB = 132\degree​​

    A.

    62o

    B.

    66o

    C.

    64o

    D.

    60o

    Correct option is B

    Given: 

    AGB=132°\angle AGB = 132\degree 

    Concept Used: 

    In a circle , Angle made on the center is two time the angle made on the circumference by the same arc.

    Solution: 

    ACB=AGB2=1322=66°\angle ACB = \frac{\angle AGB}{2} = \frac{132}{2} = 66\degree​​

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