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    In a circle with center O, PQ and RS are two chords. PQ and RS, when produced, meet at point K. If PR is a diameter and ∠ PKS = 66°, what is the value
    Question

    In a circle with center O, PQ and RS are two chords. PQ and RS, when produced, meet at point K. If PR is a diameter and ∠ PKS = 66°, what is the value of ∠ QOS?

    A.

    60°

    B.

    48°

    C.

    40°

    D.

    55°

    Correct option is B

    Given:
    PR is a diameter of the circle.
    PQ and RS are chords that meet at point K when produced.
    Angle PKS = 66°
    Formula Used:
    Angle between two secants intersecting outside the circle = 12 \frac{1}{2}​ × (Difference of intercepted arcs)
    Solution: 

    Since PR is the diameter, the measure of arc PR is 180°.
    The intercepted arcs for secants KQP and KSR are arc PR and arc QS.
    Angle PKS = arcPRarcQS2\frac{arc PR - arc QS}{2}​​
    Substitute the known values into the formula.
    66=180arcQS266 = \frac{180 - arc QS}{2}​​
    132 = 180 - arc QS
    arc QS = 180 - 132
    arc QS = 48
    The central angle subtended by an arc is equal to the degree measure of that arc.
    Angle QOS = 48°
    Final Answer
    So the correct answer is (b)

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