A circle is inscribed in a right triangle with legs of length 5 and 12. What is the radius of the circle?

Correct option is A

Given:
Length of first leg, a = 5
Length of second leg, b = 12
Formula Used:
For a right triangle, the radius of the inscribed circle is:
r = (a + b - c) / 2
where c is the hypotenuse.
Solution:
First, find the hypotenuse using Pythagoras theorem:
c = √(a² + b²)
= √(5² + 12²)
= √(25 + 144)
= √169 = 13
Now substitute the values:
r = (5 + 12 - 13) / 2
= 4 / 2
= 2