Correct option is D
Given:
We have the following sequence of integers:
8, 3, 4, 9, 3, 5, 9, 5, 9, 9, 9, 4, 5, 9, 5, 6, 3, 3, 5, 7, 2, 3, 9, 9, 8, 9, 3, 9, 1, 9, 4
We need to find how many 9s are divisible by their immediate next terms.
Solution:
We locate all 9s in the sequence and check divisibility by the next number.
9, 3 → 9 ÷ 3 = 3
9, 5 → 9 ÷ 5 = Not divisible
9, 5 → 9 ÷ 5 = Not divisible
9, 9 → 9 ÷ 9 = 1
9, 9 → 9 ÷ 9 = 1
9, 4 → 9 ÷ 4 = Not divisible
9, 5 → 9 ÷ 5 = Not divisible
9, 9 → 9 ÷ 9 = 1
9, 8 → 9 ÷ 8 = Not divisible
9, 3 → 9 ÷ 3 = 3
9, 1 → 9 ÷ 1 = 9
9, 4 → 9 ÷ 4 = Not divisible
Count of valid cases:
Six 9s are divisible by their next term.
Final Answer:
(D) 6
