In ΔOPQ, right-angled at P, OP = 7 cm and OQ - PQ = 1 cm.
Formula used
sin Q = P/H and cos Q = B/H
then
Since it is a right-angled triangle,
OQ2 = OP2 + PQ2
OQ2 – PQ2 = OP2
(OQ - PQ)(OQ + PQ) = 72
(1)(OQ + PQ) = 72
(OQ + PQ) = 49
OQ = (49 + 1)/2 = 25
PQ = (49 - 1)/2 = 24
sin Q = P/H = 7/25
cos Q = B/H = 24/25
sin Q + cos Q = 7/25 + 24/25 = 31/25
English
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60 Mins English English20 Questions40 Marks12 Mins English English80 Questions160 Marks60 Mins EnglishIn △ABC, AB = AC = 12 cm, BC = 5 cm and D is a point on AC such that DB = BC. What is the measure of CD?
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