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    A right triangle ABC is inscribed in a circle with a diameter of 10 cm. An altitude BD is drawn from the vertex B to the hypotenuse AC. If the length
    Question

    A right triangle ABC is inscribed in a circle with a diameter of 10 cm. An altitude BD is drawn from the vertex B to the hypotenuse AC. If the length of the leg AB is 6 cm, what is the length of the segment AD?

    A.

    3.6 cm

    B.

    4 cm

    C.

    4.8 cm

    D.

    6 cm

    Correct option is A

    Given :

    A right triangle \triangle ​ABC is inscribed in a circle of diameter 10 cm.
    So, hypotenuse AC = 10 cm.
    AB = 6 cm.
    BD is the altitude from B to hypotenuse AC, meeting it at D.

    Formula Used :

    In a right triangle, the projection of a leg on the hypotenuse:
    AD = AB2AC\frac{AB^2}{AC}​​
    Solution :

    AD =6210 \frac{6^2}{10}​​
    =3610 \frac{36}{10}​​
    = 3.6 cm

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