In how much time a monkey will touch the top of a pillar whose height is 60 feet if he jumps 3 feet in a second and immediately slips 2 feet ?

Correct option is A

Given:
Height of pillar = 60 feet
Jump distance = 3 feet
Slip distance = 2 feet
Formula Used:
Time taken = $$\frac{Total\ Height - Last\ Jump}{Net\ Climb\ per\ cycle}$$​ + 1 cycle
Solution:
The effective climb in 1 second is 3 feet (up) - 2 feet (down) = 1 foot.
For the final jump to reach the top, the monkey will jump 3 feet and touch the top without slipping back.
So, we calculate the time taken to reach a height from which a single jump reaches the top: 60 - 3 = 57 feet.
Time taken to effectively climb 57 feet = $$\frac{57}{1} = 57$$​ seconds.
In the next 1 second (the 58th second), the monkey jumps 3 feet upwards and touches the top (57 + 3 = 60 feet).
Total time = 57 + 1 = 58 seconds.
Final Answer
So the correct answer is (a)