Correct option is D
Given:
A can do work in 15 days
B can do work in 20 days
Formula Used:
Work = Rate × Time
Solution:
Total work = LCM of 15 and 20 = 60 units
A’s 1 day work = = 4 units
B’s 1 day work = = 3 units
Work done in 2 days = 4 + 3 = 7 units
In 16 days (8 cycles): 7 × 8 = 56 units
Remaining work = 60 − 56 = 4 units
A completes remaining work in 1 day.
Total days =16 +1 = 17 days