In classical square of opposition, if 'Some S is not P' is given as false, then which of the following could be immediately inferred from it?
(A) 'Some S is P' is true

(B) 'Some S is P' is undetermined

(C) 'Some S is P' is false

(D) 'All S is P' is undetermined

(E) 'All S is P' is true

Choose the correct answer from the options given below:

Correct option is B

In the classical square of opposition, 'Some S is not P' is an O-proposition (Particular Negative). If this proposition is false, it's contradictory, the A-proposition ('All S is P' - Universal Affirmative), must be true. This is because the relationship between A (Universal Affirmative) and O (Particular Negative) is one of contradiction; if one is false, the other must be true.
Given that 'All S is P' is true, we can also infer that 'Some S is P' (I-proposition, Particular Affirmative) is true. This is because the truth of a universal affirmative entails the truth of its corresponding particular affirmative (subalternation).
Inference Breakdown: · A-proposition (All S is P) is true because it is the contradictory of the false O-proposition.
· I-proposition (Some S is P) is true because a universal affirmative implies a particular affirmative.
Information Booster: 1. A-proposition: 'All S is P' (Universal Affirmative).
2. I-proposition: 'Some S is P' (Particular Affirmative).
3. O-proposition: 'Some S is not P' (Particular Negative).
4. Contradiction Relationship: A and O propositions are contradictories, meaning one must be true, and the other must be false.
5. Subalternation Relationship: If the A-proposition (Universal Affirmative) is true, the I-proposition (Particular Affirmative) must also be true.