​In an election, Candidate M received 67% of the votes, and Candidate N received 33% of the votes. If the total votes were 10,000, find the difference in the number of votes received by each candidate.

Correct option is D

Given:

Candidate M received 67% of the votes

Candidate N received 33% of the votes

Total votes = 10,000

Formula Used:

​$$\text{Votes} = \frac{\text{Percentage} \times \text{Total Votes}}{100} \quad \\ \ \\\text{Difference} = \text{Votes}_M - \text{Votes}_N$$​​

Solution:

​$$\text{Votes for M} = \frac{67 \times 10000}{100}$$​​

=  6700​

Votes for N = $$\frac{33 \times 10000}{100}$$​​

= 3300

Difference = 6700 - 3300 = 3400

Thus, the correct option is (d) 3400

Alternate method:

M             N

67%        33%

Difference = 67% - 33% = 34%

Since, 100% = 10000

then, Difference = $$\frac{10000}{100\%} \times 34\%$$

= 3400 votes