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    ​In an election, Candidate M received 67% of the votes, and Candidate N received 33% of the votes. If the total votes were 10,000, find the difference
    Question

    ​In an election, Candidate M received 67% of the votes, and Candidate N received 33% of the votes. If the total votes were 10,000, find the difference in the number of votes received by each candidate.

    A.

    3500

    B.

    3000

    C.

    4200

    D.

    3400

    Correct option is D

    Given:

    Candidate M received 67% of the votes

    Candidate N received 33% of the votes

    Total votes = 10,000

    Formula Used:

    Votes=Percentage×Total Votes100 Difference=VotesMVotesN\text{Votes} = \frac{\text{Percentage} \times \text{Total Votes}}{100} \quad \\ \ \\\text{Difference} = \text{Votes}_M - \text{Votes}_N​​

    Solution:

    Votes for M=67×10000100\text{Votes for M} = \frac{67 \times 10000}{100}​​

    =  6700​

    Votes for N = 33×10000100\frac{33 \times 10000}{100}​​

    = 3300

    Difference = 6700 - 3300 = 3400

    Thus, the correct option is (d) 3400

    Alternate method:

    M             N

    67%        33%

    Difference = 67% - 33% = 34%

    Since, 100% = 10000

    then, Difference 10000100%×34%\frac{10000}{100\%} \times 34\%

    = 3400 votes


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