In ∆ABC, if ∠A = 3 ∠B and ∠C = 2 ∠B then, what are values of ∠A, ∠B and ∠C?

Correct option is B

Given:

In triangle △ABC,

​$$\angle A = 3\angle B,\quad \angle C = 2\angle B$$​

Concept Used:
Sum of angles in a triangle is always $$180^\circ$$​​

Solution:

​$$3\angle B + \angle B + 2\angle B = 180^\circ$$​

​$$6\angle B = 180^\circ$$​

​$$\angle B = 30^\circ$$

Now,

​$$\angle A = 3 \times 30^\circ = 90^\circ,\quad \angle C = 2 \times 30^\circ = 60^\circ$$